The moment of inertia of a rod about an axis through its centre and perpendicular to it, is `(1)/(12)ML^(2)` (where, M is the mass and L is length of the rod). The rod is bent in the middle, so that two halves make an angle of `60^(@)`. The moment of inertia of the bent rod about the same axis would be

Answer

a

Explanation

Since rod is bent at the middle, so each part of will have same length `L/2` and mass `M/2` as shown.
Moment of inertia of each part through its one end `=1/2(M/2)`
Hence, net moment of inertia through its middle point O is
`I=1/3(M/2)(L/2)^(2) +1/3(M/2)(L/2)^(2) =1/3[(ML^(2))/8 + (ML^(2))/8] = (ML^(2))/12`