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A constant external torque tau acts for ...

A constant external torque `tau` acts for a very brief period `/_\t` on a rotating system having moment of inertia `I` then

A

The angular momentum of the system will change by `tau Deltat`

B

The angular velocity of the system will change by `(tauDeltat)/I`

C

If the system was initially at rest, it will acquire rotational kinetic energy `(tauDeltat)^(2)/(2I)`

D

The kinetic energy of the system will change by `(tauDeltat)^(2)/I`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C

Let L= angular momentum
`tau = (dL)/(dt)` or `dL= tau dt`
For constant torque,
`DeltaL = tau Deltat = I Deltaomega` or `Iomega` if `omega_(i)=0`
Rotational kinetic energy `=1/2 Iomega^(2) = (DeltaL)^(2)/(2I)`
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