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Conisder an electric field vecE=E0hatx w...

Conisder an electric field `vecE=E_0hatx` where `E_0` is a constant .
The flux through the shaded area (as shown in the figure) due to this field is

A

`2E_(0)a^(2)`

B

`sqrt(2)E_(0) a^(2)`

C

`E_(0) a^(2)`

D

`(E_(0) a^(2))/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
Electric flux `phi = E .S ` or ` phi = E S cos theta `
Here `theta` is the angle between E and S .
In this equation `theta = 45^(@)`, because S is perpendicluar ot surface .
`E = E_(0) " "," " S = (sqrt(2a))(a) = sqrt(2)a^(2)`
`therefore phi = (E_(0)) (sqrt(2)a^(2)) cos 45^(@) = E_(0) a^(2) `. Hence , option (C) is correct.
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