One mole of He gas at 0.6 atm takes 40 s to diffuse through a pin hole. Calculate the time required for diffusion of half mole of `CH_(4)` gas at 1.2 atm through the same hole.

Explanation

To solve the problem, we will use Graham's Law of Effusion, which states that the rate of effusion (or diffusion) of a gas is inversely proportional to the square root of its molar mass. The formula can be expressed as:

\[ \frac{R_1}{R_2} = \sqrt{\frac{M_2}{M_1}} \]

Where:
- \( R_1 \) and \( R_2 \) are the rates of diffusion of gas 1 and gas 2, respectively.
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