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Compound 'A' (molecular formula C(3)H(8)...

Compound 'A' (molecular formula `C_(3)H_(8)O`) is treated with acidified potassium dichromate to form a product 'B' (molecular formula `C_(3)H_(6)O`)'B' forms a shining silver mirror on warming with ammoniacal silver nitrate 'B' when treated with an aqueous solution of `H_(2)NCONHNH_(2)` and sodium acetate gives a product 'C'. Identify the structure of 'C'

A

`CH_(3)CH_(2)CH=N-NHCONH_(2)`

B

`CH_(3)-underset( CH_(3))underset(|)(C ) =N-CONH_(2)`

C

`CH_(3)-underset( CH_(3))underset( |)(C ) = N -CONHNH_(2)`

D

`CH_(3)CH_(2)CH=N-CONHNH_(2)`

Text Solution

Verified by Experts

Compound A is primary alcohol because on oxidation it is given an aldehyde 'B' which form shining mirror with ammonical silver nitrate ( Tollen's reagent ) .
Thus, compound A is
`CH_(3) -CH_(2)-CH_(2)OH ( C_(3)H_(8)O)`
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Compound A (molecular formula C_(3)H_(8)O ) is treated with acidified potassium dichromate to form a product B (molecular formula C_(3)H_(6)O ) . B forms a shining silver mirror on warming with ammonical silver nitrate , B when treated with an aqueous solution of NH_(2)NHCONH_(2) and sodium acetate gives a product C . identify the structure of C .

Compound A (molecular formula C_(3)H_(8)O) is treated with acidified potassium dichromate to from a product B (molecular formula C_(3)H_(6)O . B forms shining silver mirror on warming with ammoniacal silver nitrate. Bwhen treated with an aqueous solution of H_(2)NCONHNH_(2) , HCI and solution acetate gives a productC. Identify the structure of C.