`BF_(3)` forms an adduct with `NH_(3)` because

Options

A. Nitrogen has high electronegativity
B. Boron has smaller atomic radius than nitrogen
C. Boron has an empty 'p' orbital and nitrogen has a lone pair of electrons
D. Boron has electropositive character

Answer

C

Explanation

In `BF_(3)`, boron is electron deficient and in `NH_(3)`, nitrogen has a lone pair of electrons, hence both from a covalent bond.