If surface tension of H,O is 7.3 x 102 Nm^-1. The excess pressure inside spherical drop of radius 1 mm is

Options

A. `146N m^-2`
B. `126N m^-2`
C. `256N m^-2`
D. `746N m^-2`

Answer

A

Explanation

Pressure inside spherical drop, `P=(2T)/r`
Surface tension,`T=7.3 xx 10^(-2) N//m`
`therefore P = (2xx7.3xx10^(-2))/(1xx10^(-3) = 146 N//m^(2)`