If the length of a stretched string is shortened by 40 % and the tension is increased by 44% then ratio of the final and initial fundamental frequencies is

Options

A. `2:1`
B. `3:2`
C. `3:4`
D. `1:3`

Answer

A

Explanation

Given that length is shortened by 40% and tension is increased by 44%
`implies ` The new length and tension are,
Fundamental frequency `n=1/(2l)sqrt(T/m)`
`n_2/n_1=l_1/l_2sqrt(T_2/T_1)`
`n_2/n_1=100/600sqrt(144/100)`
`n_2:n_1=2:1`