The distance travelled by a body and the time t are related by `x=4-3t+2t^(2)m` .The average velocity in a time interval of 1 to 4 sec is m/s

Find average speed in time interval t= 2 to t=10s

If the distance s travelled by a body in time t is given by s = a/t + bt^2 then the acceleration equals

A body moves in a straight line along x-axis, its distance from the origin is given by the equation x = 8t-3t ^(2). The average velocity in the interval from t =0 to t =4 is

The distance travelled by a particle in time t is given by x = kt^3 , where k = 10 m s^(-3) . The average speed of the particle from t = 1 s to t = 5 s is

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

The equation of distance travelled by a body s with time t is given as S=A(t+B)+Ct^(2) . The dimension of B is given by

A particle moves in a straight line, its position (in m) as function of time is given by x = (at^2 + b) . What is average velocity in time interval t = 3 sec to t = 5 sec ? (Where a and b are constant and a = 1 m//s^2, b = 1 m .)

The position of a particle moving on the x-axis is given by x=t^(3)+4t^(2)-2t+5 where x is in meter and t is in seconds (i) the velocity of the particle at t=4 s is 78 m//s (ii) the acceleration of the particle at t=4 s is 32 m//s^(2) (iii) the average velocity during the interval t=0 to t=4 s is 30 m//s (iv) the average acceleration during the interval t=0 to t=4 s is 20 m//s^(2)

A particle moves in a straight line. Its position ( in m) as function of time is given by x = (at^2 + b) What is the average velocity in time interval t = 3s to t = 5s in ms^(-1) . (where a and b are constants and a = 1ms^(-2), b = 1m ).