If `A=[[1,2,2], [2,1,2],[2,2,1]]`then `A^(2)-5I=`

If A=[[1,2,22,1,22,2,1]], then prove that A^(2)-4A-5I,=O

If A=[(1,2,2),(2,1,2),(2,2,1)] then (A) A^-1= 1/5(A-4I_3) (B) A^2-4A-5I_3=0 (C) A^2 is invertible (D) A^3 is non invertible

If A=[[2, 2, 1], [1, 3, 1], [1, 2, 2]], and A^(-1)+(A-5I)(A-I)^(2)=

" 2.Let "A=[[1,0,2],[2,0,1],[1,1,2]]," then "(det((A-I)^(3)-4A))/(5)" is "

If A=|(1,2,2),(2,1,2),(2,2,1)|, verifty that A^2-4A-5I-5I=0

If A = [(2,2,1), (1,3,1), (1,2,2)] then A^-1+(A-5I) (AI)^2 = (i) 1/ 5 [[4,2, -1], [-1,3,1], [-1,2,4]] (ii) 1/5 [[4, -2, -1], [-1, 3, -1], [-1, -2,4]] (iii) 1/3 [[4,2, -1], [-1,3,1], [-1,2,4]] (iv) 1/3 [[4, -2, -1], [-1,3, -1], [-1, -2,4]]

if A=[[1,2,22,1,22,2,1]] then find the value of A^(2)-4A+5I_(3) then find the value of

Given that A=[[5,7,3],[1,5,2],[3,2,1]] and A^(3)-kA^(2)+lA=I then

If A=[{:(1,2,2),(2,1,2),(2,2,1):}] , prove that A^(2)-4A-5I=O and hence, obtain A^(-1) .