The equation of displacement of two waves are given as `y_(1)=10sin(3 pi t+(pi)/(3))`,`y_(2)=10sin(3 pi t+(pi)/(3))` .Then what is the ratio of their amplitudes

The equation of displacement of two waves are given as y_(1) = 10 sin( 3 pi t + (pi)/(3)) , y_(2) = 5 [ sin 3 pi t + sqrt(3) cos 3 pi t] Then what is the ratio of their amplitudes

The S.H.M.s of two particles are given by y_(1)=10 "sin" [2pi t +(pi)/(6)] " and " y_(2) =5["sin" 2pi t + sqrt(3) "cos" 2 pi t] The ratio of their amplitudes is

Two particle are executing SHMs .The equations of their motions are y_(1)=10"sin"(omegat+(pi)/(4)) " and "y_(2)=5 "sin"(omegat+(sqrt(3)pi)/(4)) What is the ratio of their amplitudes.

If two particles performing SHM, are given by, x_(1)=10 sin[3pi t +(pi//4)] and x_(2)=5[sin 3pi t +sqrt(3) cos 3 pi t] then the ratio of their amplitudes is

If two SHMs are represented by equations y_1 = 4 sin[3 pi t + ( pi /3)], y_2 = 4 [sin(3 pi t) + sqrt 3 cos (3 pi t)], then the ratio of their amplitudes is

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

If two SHMs are represented by equations y_(1) = 5 sin (2pi t + pi//6) and y_(2) = 5 [sin (3pi) + sqrt3 cos (3pi t)] . Find the ratio of their amplitudes.

Two simple harmonic motions are represented by y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4)) The ratio of their amplitudes is

Two simple harmonic motions are represented by the equations. y_(1)=10"sin"(pi)/(4)(12t+1),y_(2)=5(sin3pt+sqrt(3)cos3pt) the ratio of their amplitudes is

The relation between time and displacement for two particles is given by y = 0.06 sin 2 pi (0.04 t + phi_(1)),y_(2) = 0.03 sin 2 pi (1.04 t + phi_(2)) The ratio of the intensities of the waves produced by the vibrations of the two particles will be