A miscible mixture of `C_(6)H_(6)+CHCl_(3)` can be separated by

Options

A. Sublimation
B. Distillation
C. Filtration
D. Crystallisation

Answer

To separate a miscible mixture of benzene (C₆H₆) and chloroform (CHCl₃), we can use the process of distillation. Here's a step-by-step solution:

### Step-by-Step Solution:

1. **Identify the Components**: The mixture consists of benzene (C₆H₆) and chloroform (CHCl₃). Benzene is a non-polar solvent, while chloroform is polar.

2. **Understand the Properties**: Benzene has a boiling point of approximately 80.1 °C, while chloroform has a boiling point of about 61.2 °C. The significant difference in their boiling points indicates that they can be separated by distillation.

3. **Set Up the Distillation Apparatus**: Use a distillation setup, which typically includes a distillation flask, a condenser, and a receiving flask. Ensure that the apparatus is properly assembled to avoid any loss of vapors.

4. **Heat the Mixture**: Gradually heat the mixture in the distillation flask. As the temperature rises, the component with the lower boiling point (chloroform) will vaporize first.

5. **Collect the Vapors**: The vapor produced will travel through the condenser, where it will cool and condense back into a liquid. This liquid will be collected in the receiving flask.

6. **Continue Heating**: Continue heating until most of the chloroform has been distilled off. Once the temperature rises to the boiling point of benzene, benzene will start to vaporize.

7. **Collect Benzene**: After the chloroform has been mostly removed, you can collect the benzene that vaporizes and condenses in the receiving flask.

8. **Final Separation**: By repeating the distillation process, you can achieve a higher purity of both components.

### Conclusion:
The separation of benzene and chloroform can be effectively achieved through distillation due to the difference in their boiling points.

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