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The glass of optical fibre has a refract...

The glass of optical fibre has a refractive index 1.55 and cladding with another glass of refractive index 1.51. When the surrounding medium is air, the numerical aperture will be

A

0.625

B

`0.350`

C

`0.528`

D

0.704

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The correct Answer is:
To find the numerical aperture (NA) of the optical fiber, we can use the formula: \[ \text{NA} = \sqrt{n_1^2 - n_2^2} \] where: - \( n_1 \) is the refractive index of the core (glass of optical fiber), - \( n_2 \) is the refractive index of the cladding. ### Step-by-step Solution: 1. **Identify the Refractive Indices**: - The refractive index of the core, \( n_1 = 1.55 \). - The refractive index of the cladding, \( n_2 = 1.51 \). 2. **Substitute the Values into the Formula**: \[ \text{NA} = \sqrt{(1.55)^2 - (1.51)^2} \] 3. **Calculate \( n_1^2 \) and \( n_2^2 \)**: - Calculate \( (1.55)^2 \): \[ (1.55)^2 = 2.4025 \] - Calculate \( (1.51)^2 \): \[ (1.51)^2 = 2.2801 \] 4. **Subtract \( n_2^2 \) from \( n_1^2 \)**: \[ 2.4025 - 2.2801 = 0.1224 \] 5. **Take the Square Root**: \[ \text{NA} = \sqrt{0.1224} \approx 0.349 \] 6. **Round the Result**: - The numerical aperture can be approximated to \( 0.350 \). ### Final Answer: The numerical aperture (NA) of the optical fiber is approximately \( 0.350 \).
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