(x^(2)y^(3)+2xy)dy=dx

the solution of (dy)/(dx)(x^(2)y^(3)+xy)=1

Solve (x^(3)-3xy^(2))dx+(3x^(2)y-y^(3))dy=0

Solve the following differential equations (i) (1+y^(2))dx = (tan^(-1)y - x)dy (ii) (x+2y^(3))(dy)/(dx) = y (x-(1)/(y))(dy)/(dx) + y^(2) = 0 (iv) (dy)/(dx)(x^(2)y^(3)+xy) = 1

The solution of dy/dx (x^(2)y^(3)+xy)=1 is -

(x^2y^3+xy)dy=dx

(x^2y^3+xy)dy=dx

Solve (dy)/(dx)=(x^(2)+3y^(2))/(2xy)

Which of the following is a homogeneous differential equation? (A) (4x+6y+5)dy-(3y+2x+4)dx= (B) (xy)dx-(x^(3)+y^(3))dy=0 (C) quad y^(2)dx+(x^(2)-xy-y^(2))dy=0

y^(2)dx+(x^(2)+xy+y^(2))dy=0

y The differential equation of all circles passing through the origin and having their centres on the x-axis is (1)x^(2)=y^(2)+xy(dy)/(dx) (2) x^(2)=y^(2)+3xy(dy)/(dx)y^(2)=x^(2)+3xy(dy)/(dx)y^(2)=x^(2)-2xy(dy)/(dx)