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The energy needed for the following proc...

The energy needed for the following process is
`Li(g) to Li^(3+) (g)+3e^(-)`
If the first ionization energy of lithium is `520" kJ mol"^(-1)`, calculate the second ionization energy of lithium, that is the energy required for the process.
`Li^(+) (g) to Li^(2+) (g)+e^(-)`

Text Solution

Verified by Experts

`Li overset(-e^(-))Li^(+) overset(e^(-)) Li^(2+) overset(e^(-))to Li^(3+)`
Total energy required `=1.96 xx 106(4)=19600"kJ mol"^(-1)`
`I.E_(1)=520kJ mol^(-1), I.E_(3)=(1312 xx Z^(2))/(n^(2))=(1312 xx 9)/(1) =11808`
`I.E_(1)+I.E_(3)=12328kJ mol^(-1)`
`I.E_(2)=19600-12328=7272"kJ mol"^(-1)`
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