(a-b)/(c)=(sin((A-B)/(2)))/(cos(C)/(2))

In a triangle ABC if (sin2A+sin2B+sin2C)/(cos A+cos B+cos C-1)=((lambda)/(2))cos((A)/(2))cos((B)/(2))cos((C)/(2)) then lambda equals

In any triangle ABC, prove that : (a-b)/c= (sin frac (A-B)(2))/(cos frac (C)(2)) .

If A+B+C=pi then prove that cos A+cos B+cos C=1+4sin((A)/(2))*sin((B)/(2))*sin((C)/(2))

If A + B + C = 180^(@) then P.T. "cos "(A)/(2) + sin ((B - C)/(2)) = 2 "sin" (B)/(2) "cos" (C )/(2)

In any triangle ABC prove that: sin((B-C)/(2))=((b-c)/(a))(cos A)/(2)

sin A + sin B + sin C = 4cos ((A) / (2)) cos ((B) / (2)) cos ((C) / (2))

cos A + cos B + cos C = 1 + 4sin ((A) / (2)) sin ((B) / (2)) sin ((C) / (2))

(sin2A+sin2B+sin2C)/(cos A+cos B+cos C-1)=((lambda)/(2))(cos A)/(2)(cos B)/(2)(cos C)/(2) then lambda=

In any triangle ABC, prove that following: sin((B-C)/(2))=(b-c)/(a)(cos A)/(2)