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Ring is fixed on the horizontal surface ...

Ring is fixed on the horizontal surface and a rod starts rotatiing with constant angular velocity `omega` fixed at O as shown in the figure. Find the magnitude of velocity of intersection points of rod and ring when `aplha` become `90^(@)`

A

`sqrt(R^(2)-2r^(2)omega)`

B

`sqrt(R^(2)-2^(2)omega)`

C

`(Romega)/(2)`

D

`Romega`

Text Solution

Verified by Experts

The correct Answer is:
d
Velocity of points A which lie on road =`r omega` So velocity of intersection points vos`theta`= r`omega`
`impliesv=(r.omegaR)/(r.)=Romega`
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