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" 3."tan20^(@)cot70^(@)-sec20^(@)dosec70...

" 3."tan20^(@)cot70^(@)-sec20^(@)dosec70^(@)

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The value of (1+sec20^(@)+cot70^(@))(1-"cosec"20^(@)+tan70^(@)) is equal to

(tan40^(@)+tan20^(@))/(cot45^(@)-cot50^(@)cot70^(@))=(A)sqrt(3)(B)1(C)0(D)-1

sec70^(@)sin20^(@)+cos20^(@)cosec70^(@)=2

sec70^(@)sin20^(@)+cos20^(@)"cosec"70^(@)=?

Evaluate (sin35^(@))/(cos55^(@))+(sec20^(@))/("cosec"70^(@)) .

Evaluate (sin35^(@))/(cos55^(@))+(sec20^(@))/("cosec"70^(@)) .

Evaluate : 2((cos65^(@))/(sin25^(@)))-(tan20^(@))/(cot70^(@))-sin90^(@)+tan5^(@)tan35^(@)tan60^(@)tan55^(@)tan85^(@)

Evaluate : 2((cos65^(@))/(sin25^(@)))-(tan20^(@))/(cot70^(@))-sin90^(@)+tan5^(@)tan35^(@)tan60^(@)tan55^(@)tan85^(@)

Prove that tan20^(@)+tan70^(@)=(sec^(2)20^(@))/(sqrt(sec^(2)20^(@)-1))

Without using Trigonometric Tables evaluate the following :- ((tan20^@)/(cosec70^@))^2+((cot20^@)/sec70^@)+2tan15^@tan37^@tan53^@tan60^@tan75^@ .