The total electric flux leaving a spherical surface of radius 1 cm and surrounding an electric dipole is

Options

A. `q/(epsilon_(0))`
B. zero
C. `(2q)/(epsilon_(0))`
D. infinite

Explanation

To solve the problem of finding the total electric flux leaving a spherical surface of radius 1 cm that surrounds an electric dipole, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Electric Dipole**: An electric dipole consists of two equal and opposite charges, +q and -q, separated by a distance. The dipole moment (p) is defined as \( p = q \cdot d \), where \( d \) is the distance between the charges.

2. **Identify the Gaussian Surface**: We consider a spherical Gaussian surface of radius 1 cm surrounding the dipole. According to Gauss's Law, the electric flux (\( \Phi \)) through a closed surface is given by:
\[ \Phi = \frac{Q_{\text{inside}}}{\epsilon_0} \]
where \( Q_{\text{inside}} \) is the total charge enclosed by the surface and \( \epsilon_0 \) is the permittivity of free space.

3. **Calculate the Total Charge Inside the Gaussian Surface**: For an electric dipole, the total charge is:
\[ Q_{\text{inside}} = +q + (-q) = 0 \]
Since the dipole consists of equal and opposite charges, the net charge enclosed by the Gaussian surface is zero.

4. **Apply Gauss's Law**: Substituting \( Q_{\text{inside}} = 0 \) into Gauss's Law gives:
\[ \Phi = \frac{0}{\epsilon_0} = 0 \]

5. **Conclusion**: The total electric flux leaving the spherical surface surrounding the electric dipole is zero.

### Final Answer:
The total electric flux leaving the spherical surface surrounding the electric dipole is **0**.

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