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Ratio of kinetic energy to potential ene...

Ratio of kinetic energy to potential energy of an oscillator when it is at distance `1//N` times of amplitude from mean positions in

A

`N^(2) + 1`

B

`N^(2)`

C

`(1)/(N^(2))`

D

`N^(2) - 1`

Text Solution

Verified by Experts

The correct Answer is:
D

`(K)/(U) = ((1)/(2) m omega^(2) (A^(2) - x^(2)))/((1)/(2) m omega^(2) x^(2)) = (A^(2) - ((A)/(N))^(2))/(((A)/(N))^(2)) = N^(2) - 1`
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