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Balance the following by ion electron me...

Balance the following by ion electron method is basic medium.
`NO_(3)^(ө)+Znrarr Zn^(2+)+NH_(4)^(oplus)`.

Text Solution

Verified by Experts


(ii) `Zn rarr Zn^(2+)` (Oxidation half reaction)
`" " NO_(3)^(-) rarr NH_(4)^(+)` (Reduction half reaction)
(iii) Balancing `e^(-)`
`" "Zn rarr Zn^(2+)+2e^(-)`
`" "NO_(3)^(-)+8e^(-) rarr NH_(4)^(-)`
(iv) Balancing .O.
`" "Zn rarr Zn^(2+)+2e^(-)`
`" "NO_(3)^(-)+8e^(-) rarr NH_(4)^(+)+3H_(2)O`
(v) Balancing .H.
`" "NO_(3)^(-)+8e^(-)+10H_(2)O rarr NH_(4)^(+)+3H_(2)O+10OH^(-)`
`" "Zn rarr Zn^(2+)+2e^(-)`
`NO_(3)^(-)+7H_(2)O+8e^(-) rarr NH_(4)^(+)+10OH^(-)`
Now,
`" "[Zn rarr Zn^(2+)+2e^(-)] times 4`
`" "NO_(3)^(-)+7H_(2)O+8e^(-) rarr NH_(4)^(+)+10OH^(-)`
`" "bar(4Zn+NO_(3)^(-)+7H_(2)O rarr 4Zn^(2+)+NH_(4)^(+)+10OH^(-))`
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