If the velocity of the electron in Bohr's first orbit is `2.19 xx 10^(6) ms^(-1)`. Calculate the de-Broglie wavelength with it.

Explanation

We know, mass of electron = `9.1 xx 10^(-31) kg`
`h = 6.626 xx 10^(-34) Js`
`:. Lambda =h/(mv) = (6.626 xx 10^(-34))/(9.1 xx 10^(-31) xx 2.19 xx 10^6)`
`= 3.32 xx 10^(-10) m`.