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Question: When a potential diffference o...

Question: When a potential diffference of 2 V is applied across the ends of a wire of 5 m length, a current of 1 A is found to flow through it.
Calculate :
The resistance per unit length of the wire

Text Solution

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When the wire is doubled on itself :
(a) The area of cross-section is doubled,. If A is the original C.S. area, now it is 2 A
(b) The length becomes half i.e. L/2
Resistance of this wire`=R.=p(1//2)//(2A)=1//4(p(L//A)`
But p(L/A)=2 ohm
R.=1/4`xx2=0.5` Ohm
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