" If "tan^(2)Theta+sec^(2)Theta=1," then "Theta=

If 1+ tan^(2) theta = sec^(2) theta then find (sec theta + tan theta)

If 1+ tan^(2) theta = sec^(2) theta then find (sec theta + tan theta)

Statement 1: tan^(2)(sec^(-1)2)+cot^(2)(cosec^(-1)3)=11 . Statement -2 :tan^(2)theta+sec^(2)theta=1=cot^(2)theta+cosec^(2)theta

Statement 1: tan^(2)(sec^(-1)2)+cot^(2)(cosec^(-1)3)=11 . Statement -2 :tan^(2)theta+sec^(2)theta=1=cot^(2)theta+cosec^(2)theta

"cosec"^(2) theta * cot^(2) theta -sec^(2) theta * tan^(2) theta - (cot^(2) theta - tan^(2) theta ) (sec^(2) theta * "cosec"^(2) theta -1)=

The value of cosec ^(2) theta cot ^(2) theta - sec ^(2) theta tan ^(2) theta -(cot ^(2) theta- tan ^(2) theta) (sec ^(2) theta cosec ^(2) theta -1) is-

If a chord joining P(a sec theta, a tan theta), Q(a sec alpha, a tan alpha) on the hyperbola x^(2)-y^(2) =a^(2) is the normal at P, then tan alpha is (a) tan theta (4 sec^(2) theta+1) (b) tan theta (4 sec^(2) theta -1) (c) tan theta (2 sec^(2) theta -1) (d) tan theta (1-2 sec^(2) theta)

STATEMENT-1: tan(sec^(-1)2+cot^(2)(cos ec^(-1)3)=11 STATEMENT-2:tan^(2)theta+sec^(2)theta=1=cot^(2)theta+cos ec^(2)theta

If tan theta + sec theta = n, then sec ^(4) theta - tan ^(4) theta- 2 sec theta tan theta =

1+(tan^(2)theta)/((1+sec theta))=sec theta