In the circuit diagram find the potential difference across the plates of capacitor C

Options

A. `I_(1) gt I_(2) `
B. `I_(1) lt I_(2)`
C. `V_(C) gt V'_(C)`
D. `V_(C) lt V'_(C)`

Answer

B, C

Explanation

(b,c): Current flowing in circuit can be written as follows :
`I= (V)/(sqrt(R^(2)+((1)/(omegaC))^(2)))`
Voltage across capacitor can be written as follows :
`V_(C) = Ixx(I)/(omegaC)`
`implies V_(C) = (V)/(sqrt(R^(2)+((1)/(omegaC))^(2)))xx(1)/(omegaC)`
`implies V_(C)= (V)/(sqrt((RomegaC)^(2)+1))`
On insertion of dielectric slab capacitance increases and due to this current inreases and voltage across capacitor decreases . Hence options (b)and (c ) are correct.