If the slope of the normal to the parabola `3y^(2) + 4y +2=x` at a point on it is 8, then the coordinates of the point are-

The slope of the normal to the parabola 3y^(2)+4y+2=x at a point it is 8. find the coordinates of the points.

The equation of the normal to the parabola y^(2)=8x at the point t is

The slope of the tangent to the parabola y^(2)=4ax at the point (at^(2), 2at) is -

The equation of the normal to the parabola y^(2)=8 x having slope 1 is

The slope of the normal to the curve x^(2) + 3y + y^(2) = 5 at the point (1,1) is

Find the slope of normal to the curve 3x^(2) - y^(2) =8 at the point (2,2)

The slopes of the normals to the parabola y^(2)=4ax intersecting at a point on the axis of the a distance 4a from its vertex are in

The slopes of the normal to the parabola y^(2)=4ax intersecting at a point on the axis of the parabola at a distance 4a from its vertex are in

The slope of the tangent line to the curve x^(3)-x^(2)-2x+y-4=0 at some point on it is. 1. Find the coordinates of such point or points.

The line y = 2x-12 is a normal to the parabola y^(2) = 4x at the point P whose coordinates are