A body is projected with a velocity `40ms^(-1)` at `30^(0)` to horizontal.Its initial velocity vector is

A body is projected with a velocity 60 ms ^(-1) at 30^(@) to horizontal . Its initial velocity vector is

A body is projected with an initial velocity 20 m//s at 60^(@) to the horizontal. Its initial velocity vector is "___" (g=10 m//s^(2))

" A body is projected with velocity u making an angle 30^(0) with the horizontal.Its velocity when it is perpendicular to the initial velocity vector is "

A body is projected with velocity 60m//s at 30^(@) to the horizontal.The velocity of the body after 3 seconds is

A ball is projected with a velocity 20 sqrt(3) ms^(-1) at angle 60^(@) to the horizontal. The time interval after which the velocity vector will make an angle 30^(@) to the horizontal is (Take, g = 10 ms^(-2))

A particle is projected with velocity u at angle theta with horizontal. Find the time when velocity vector is perpendicular to initial velocity vector.

A body is projected with a velocity of 30 ms^(-1) at an angle of 30^(@) with the vertical. Find the maximum height, time of flight and the horizontal range.

An object is projected with a velocity of 30 ms^(-1) at an angle of 60^(@) with the horizontal. Determine the horizontal range covered by the object.

A body of mass 1kg is projected with velocity 50 ms^(-1) at an angle of 30^(@) with the horizontal. At the highest point of its path a force 10 N starts acting on body for 5s vertically upward besids gravitational force, what is horizontal range of the body (Take, g = 10 ms^(-2))

A body is projected down from height of 60 m with a velocity 10 ms ^(-1) at angle 30^(@) to horizontal. The time of flight of the body is [g = 10 ms ^(-2)]