Home
Class 12
PHYSICS
In Young's double slit experiment, the s...

In Young's double slit experiment, the separatation of the slit is 2mm. The screen is at a distance 1m from the slit. How many bands can be seen in a space of 1cm? Given wavelength of light =400nm.

Text Solution

Verified by Experts

The correct Answer is:
50
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    NEW JOYTHI PUBLICATION|Exercise EVALUATION QUESTIONS AND ANSWERS|18 Videos
  • WAVE OPTICS

    NEW JOYTHI PUBLICATION|Exercise CONTINUOUS EVALUATION (assignment)|8 Videos
  • WAVE OPTICS

    NEW JOYTHI PUBLICATION|Exercise SOLUTION TO EXERCISES FROM NCERT TEXT|21 Videos
  • SEMICONDUCTOR ELECTRONICS : MATERIALS , DEVICES AND SIMPLE CIRCUITS

    NEW JOYTHI PUBLICATION|Exercise COMPETITIVE EXAM CORNER|37 Videos

Similar Questions

Explore conceptually related problems

The separation between the. consecutive dark fringes in a Young's double slit experiment is 1 mm. The screen is placed at a distance of 2.5 m from the slits and separation between the slits is 1.0 mm. Calculate the wavelength of light used for the experiment.

In Young's double slit experiment, the band width on a screen is double when the screen is moved through 1m. If te distance between the slits is 0.4mm and the wavelength of light used is 600nm , find the band width.

In a Young's double slit interference experiment the fringe pattern is observed on a screen placed at a distance D from the slits. The slits are separated by a distance d and are illuminated by monochromatic light of wavelength lamda . Find the distance from the central point where the intensity falls to (a) half the maximum,

In Young 's double slit experiment the distance between the slits and the screen is doubled the separation between the slits is reduced to half. As a result the fringe width.

In a Young's double slit experiment the separation between the slits is 0.10 mm, the wavelength of light used is 600 nm and the interference pattern is observed on a screen 1.0 m away. Find the separation between the successive bright fringes.

In a Young's double slit experiment, the separation between the slits = 2.0 mm, the wavelength of the light = 600 nm and the distance of the screen from the slits = 2.0 m. If the intensity at the centre of the central maximum is 0.20 W m^-2 , what will be the intensity at a point 0.5 cm away from this centre along the width of the fringes ?

In a single slit diffraction the distance between the first minima on either side of the central maximum is 5mm. The screen is place data distance of 75 cm from the slit and the wavelength of light used is 546nm. Calculate the slit width.

In Young's double silt experiment, the two slits are 0.15 mm apart. The light source has a wavelenght of 450 nm. The screen is 2 m away from the slits. (i) Find the distance of the second bright frings and also third dark frings from the central maximum. (ii) Find the fringe width. (iii) How will the frings pattern change if the screen is moved away from the silis? (iv) what will happen to the fringe width if the whole setup is immersed in water of refractive index 4/3.