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Representation of 0.bar(2341) in the for...

Representation of `0.bar(2341)` in the form `p //q`, where p and q are integers, `q cancel(=)0`, is

A

`( 781)/( 3330)`

B

`( 1171)/( 4995)`

C

`( 2341)/( 9999)`

D

`( 2339)/( 9990)`

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The correct Answer is:
To represent the repeating decimal \(0.\overline{2341}\) in the form of \(\frac{p}{q}\), where \(p\) and \(q\) are integers and \(q \neq 0\), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the repeating part**: The repeating decimal is \(0.\overline{2341}\). Here, "2341" is the part that repeats. 2. **Set up the equation**: Let \(x = 0.\overline{2341}\). 3. **Multiply by a power of 10**: Since "2341" has 4 digits, multiply \(x\) by \(10^4\) (which is 10000) to shift the decimal point 4 places to the right: \[ 10000x = 2341.\overline{2341} \] 4. **Subtract the original equation from this new equation**: \[ 10000x - x = 2341.\overline{2341} - 0.\overline{2341} \] This simplifies to: \[ 9999x = 2341 \] 5. **Solve for \(x\)**: Divide both sides by 9999: \[ x = \frac{2341}{9999} \] 6. **Final representation**: Thus, the representation of \(0.\overline{2341}\) in the form \(\frac{p}{q}\) is: \[ \frac{2341}{9999} \] ### Conclusion: The final answer is \(\frac{2341}{9999}\).
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