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Shantanu's cap is in the form of a right...

Shantanu's cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 5 such caps.

A

5000 sq cm

B

2750 sq cm

C

3000 sq cm

D

2700 sq cm

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The correct Answer is:
To find the area of the sheet required to make 5 caps in the shape of a right circular cone, we will follow these steps: ### Step 1: Identify the given values - Base radius (r) of the cone = 7 cm - Height (h) of the cone = 24 cm ### Step 2: Calculate the slant height (l) of the cone The slant height can be calculated using the Pythagorean theorem: \[ l = \sqrt{r^2 + h^2} \] Substituting the values: \[ l = \sqrt{7^2 + 24^2} = \sqrt{49 + 576} = \sqrt{625} = 25 \text{ cm} \] ### Step 3: Calculate the curved surface area (CSA) of one cap The formula for the curved surface area of a cone is: \[ \text{CSA} = \pi r l \] Using \(\pi \approx \frac{22}{7}\): \[ \text{CSA} = \frac{22}{7} \times 7 \times 25 \] Calculating this: \[ \text{CSA} = 22 \times 25 = 550 \text{ cm}^2 \] ### Step 4: Calculate the total area of the sheet required for 5 caps To find the total area required for 5 caps, we multiply the area of one cap by 5: \[ \text{Total Area} = 5 \times \text{CSA} = 5 \times 550 = 2750 \text{ cm}^2 \] ### Final Answer The area of the sheet required to make 5 caps is **2750 cm²**. ---
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ARIHANT SSC-VOLUME AND SURFACE AREA -FAST TRACK PRACTICE
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  19. What will be the surface area of the sphere having 4 cm radius?

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