At `25^(@)C` and 760 mm of Hg pressure a gas occupies 600 mL volume. What will be its pressure at a height where temperature is `10^(@)C `and volume of the gas is 640 mL.

Explanation

`p_(1)="760 mm Hg "p_(2)=?`
`V_(1)=600 mL" "V_(2)=640 mL`
`T_(1)=273+25=298K" "T_(2)=273+10=283K`
According to combined gas law equation,
`(p_(1)V_(1))/(T_(1))=(p_(2)V_(2))/(T_(2))`
`"or "p_(2)=(p_(1)V_(1)T_(2))/(V_(2)T_(1))`
`=((760mm Hg)xx(600mL)xx(283K))/((640 mL)(298K))`
`=676.6 mm Hg`