" (i) "(tan^(-1)x)^(2)

The solution of the inequality (tan^(-1)x)^(2)-3tan^(-1)x+2>=0 is

Solve for x:tan^(-1)((2-x)/(2+x))=(1)/(2)tan^(-1)(x)/(2),x>0

If x gt 0 then int ("tan"^(-1) (x)/(x^(2) + 1) + "tan"^(-1) " "(x^(2) +1)/(x) ) dx =

For real numbers alpha, beta, gamma and delta , if int((x^(2)-1)+tan^(-1)((x^(2)+1)/(x)))/((x^(4)+3x^(2)+1)tan^(-1)((x^(2)+1)/(x)))dx = alpha log_(e)(tan^(-1)((x^(2)+1)/(x)))+beta "tan"^(-1)((gamma(x^(2)-1))/(x))+delta tan ((x^(2)+1)/(x))+C where is an arbitrary constant, then the value of 10(alpha+betagamma+delta) is equal to........

Solve the following equations : tan^(-1) (x+2) +tan^(-1) (x-2) = tan^(-1) (8/79)

Solve the following equations : tan^(-1) (x+2) +tan^(-1) (x-2) = pi/4 , x gt 0

Solve tan^(-1)x +"tan"^(-1) (2x)/(1-x^(2))=(pi)/(2) .

int frac{1}{x^2 + 4x + 8} dx =............... A) tan^(-1) (frac{x+2}{2}) + c B) tan^(-1) (x+2) + c C) (1/4) tan^(-1) (x+2) + c D) (1/2) tan^(-1) (frac{x+2}{2}) + c

int(x tan^(-1)x^(2))/(1+x^(4))dx

If "Tan"^(-1)1/(1+2x)+"Tan"^(-1)1/(4x+1)" = Tan"^(-1)2/(x^(2)) then x(x!=0)=