The path difference between two interfering waves at a point on screen is 171.5 times the wavelength if the path difference is 0.01029 cm find the wavelength.

Options

A. `6000xx10^(-10)cm`
B. 6000 Å
C. `6000xx10^(-8)mm`
D. None of these

Answer

B

Explanation

Path difference = `171.5lamda=343/2lamda`
= odd multiple of half wavelength.
It means dark fringe is observed.
According to question, 0.01029 = `343/2lamda`
`rArrlamda=(0.01029xx2)/343=6xx10^(-5)cmrArrlamda=6000Å`.