Light of a particular frequency v is incident on a metal surface. When the intensity of incident radiation is increased, the photoelectric current

Options

A. decreases
B. increases
C. remains unchanged
D. sometimes increases and sometimes decreases

Explanation

To solve the question regarding the effect of increasing the intensity of incident radiation on the photoelectric current, we can break it down into the following steps:

### Step-by-Step Solution:

1. **Understanding the Photoelectric Effect**:
The photoelectric effect occurs when light (or electromagnetic radiation) hits a metal surface and causes the emission of electrons. This phenomenon is dependent on the frequency of the incident light and the work function of the metal.

2. **Role of Frequency**:
The frequency (ν) of the incident light must be above a certain threshold frequency for the photoelectric effect to occur. If the frequency is sufficient, photons can impart enough energy to electrons to overcome the work function of the metal.

3. **Effect of Intensity**:
The intensity of the incident light is related to the number of photons striking the surface per unit time. Increasing the intensity means that more photons are incident on the metal surface.

4. **Photon-Electron Interaction**:
Each photon can potentially eject one electron from the metal surface. Therefore, if the intensity increases, the number of photons increases, leading to a higher number of electrons being ejected.

5. **Photoelectric Current**:
The photoelectric current is directly proportional to the number of electrons emitted from the metal surface. Since more photons lead to more electrons being emitted, an increase in intensity results in an increase in the photoelectric current.

6. **Conclusion**:
Therefore, when the intensity of the incident radiation is increased, the photoelectric current also increases.

### Final Answer:
The photoelectric current increases when the intensity of incident radiation is increased.

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