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Work out the heat change (cal) when 40 g...

Work out the heat change (cal) when 40 g of He gas at `27^(@)C` undergoes isothermal and reversibel compression from initial pressure of 1 atm to 10 atm `(R=2calK^(-1)"mol"^(-1))`

A

13.818k cal

B

`-13.818` kcal

C

`55.272`kcal

D

`-55.272` k cal

Text Solution

Verified by Experts

The correct Answer is:
B
`q=-w_("rev")=-(-2.303nRT"log"(P_(1))/(P_(2)))`
`=2.303xx40/4xx2xx300"log"1/10=-13.82` kcal
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