A body is thrown vetically upward at `t = 0`. It is at a height 80 m at two instant `t_(1)` and `t_(2)`, then `t_(1) t_(2)` is: (Take `g = 10 m//s^(2)`)

A body is projected vertically upwards at time "t=0" and it is seen at a height H at instants t_(1) and t_(2)seconds during its flight.The maximum height attained is (g is acceleration due to gravity

A ball is thrown upwards from the ground. It is at a height 100 m in upward and downward journeys at time t_1 and t_2 respectively. If g = 10 m/s^(2) , then the product of t_1 . t_2 is:

A ball is thrown upwards from the ground . It is at a height of 100m in upwards and downward journeys at times t_1 and t_2 respectively , If g = 10m/s^2 , then t_1t_2 is equal to

A particle is thrown upward at t=0. It attains maximum height of h. It is found at height h/3 at t = t_1 and t = t_2 . Find t_1/t_2

A particle is thrown with a velocity of u m/s. It passes A and B as shown in figure at time t_(1) = 1 s and t_(2) = 3 s. The value of u is (g = 10 m//s^(2))

At time t=0 a body is thrown vertically upwards with a velocity "50m/sec" .At time t=2 sec another body is thrown vertically upwards with the same velocity "50m/sec" .the two bodies will meet at time__ sec (a=10m/sec^(2))

In the figure shown, find acceleration of the system and tenslons T_(1),T_(2) and T_(3) (Take = 10 m//s^(2))