If `y=a+bx^(2)," then: "`

If y=a+ bx^(2) , where a, b are constants, then

If y=a+ bx^(2) , where a, b are constants, then

If y=bx^(2)+(a//x)" then "x^(2)y_(2)=

If y=A/x + Bx^(2) , then x^(2) (d^(2)y)/(dx^(2)) =

y= ax + bx^(2)

If y=a+bx^(2) , where a, b are arbitrary constants, then

If y=sqrt(x+bx^2) , then find dy/dx

A particle is projected from the origin in X-Y plane. Acceleration of particle in Y direction is a. If equation of path of the particle is y = ax-bx^(2) , then find initial velocity of the particle.