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The emf of the following cell at 25^@C i...

The emf of the following cell at `25^@C` is equal to `0.34v`. Calculate the reduction potential of copper electrode.
`Pt(s) |H_2(g , 1 atm)|H^+ (aq, 1M)|Cu^(2+)(aq, 1M)|Cu(s)`.

Text Solution

Verified by Experts

SHE Value is Zero `" " :. E_("cell")^(@) = E_(R )^(@) - E_(L)^(@)`
`= 0.34 - 0 = 0.34 V`
The reduction potential of copper electrode = 0.34 V.
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