Hydrolysis of DDT is a first order reaction , its half life is 10 years . Time to hydrolyse 10 g DDT to half is

Options

A. 100 years
B. 50 years
C. 5 years
D. 10 years

Explanation

To solve the problem of how long it takes to hydrolyze 10 g of DDT to half its amount, we can follow these steps:

### Step 1: Understand the Concept of Half-Life
The half-life of a first-order reaction is the time required for the concentration of a reactant to decrease to half of its initial concentration. In this case, the half-life (t₁/₂) of DDT is given as 10 years.

### Step 2: Identify the Initial Amount
We start with an initial amount of 10 g of DDT.

### Step 3: Calculate the Time Required to Hydrolyze to Half
Since the half-life is independent of the initial concentration for first-order reactions, the time required to hydrolyze 10 g of DDT to half (which is 5 g) is equal to the half-life of the reaction.

### Step 4: Conclusion
Therefore, the time required to hydrolyze 10 g of DDT to half (5 g) is 10 years.

### Final Answer:
The time to hydrolyze 10 g of DDT to half is **10 years**.

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