" 3) "y=ae^(3x)+be^(-2x)

In y = ae^(3x) + be^(-2x) form the differential equation by eliminating arbitrary constant a and b .

Form a differential equation representing the given family of curves by eliminating arbitrary constants a and b y = ae^(3x) + be^(-2x)

Form a differential equation representing the given family of curves by eliminating arbitrary constants a and b . y=ae^(3x)+be^(-2x)

If y=ae^(3x)+be^(-2x) represents family of curves, where a and b are arbitrary constant. Form the differential equation.

Find the Differential equation satisfying the family of curves y=ae^(3x)+be^(-2x) ,a and b are arbitrary constants.

Form a differential equation representing the given family of curves by eliminating arbitrary constants a and b.y=ae^(3x)+be^(-2x)

(1) y = ae^(4x) -be^(-3x) +c (2) xy = ae^(5x) +be^(-5x)

The differential equation for y=ae^(x)+be^(-2x) is

Verify that y=ae^(3x)+be^(-x) is a solution of differential equation (d^2y)/(dx^2)-2(dy)/(dx)-3y=0