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Calculate the value of equilibrium cons...

Calculate the value of equilibrium constant for the reaction :
`2Fe^(3+)+2I^(-) to 2Fe^(2+)+I_(2)`
Given that `E_(cell)^(@)=0.235" V "`

Text Solution

Verified by Experts

The correct Answer is:
`9.25 xx 10^(7)`
`E_(Cell)^(Theta) = (0.0509)/(n) log K_(c)`
or log `K_(c) = (E_(cell)^(Theta))/(0.059)`
`= (2 xx 0.235)/(0.059)`
`K_(c) = 9.25 xx 10^(7)`
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