The resistance of a conductivity cell contaning `0.001M KCl` solution at `298K` is `1500Omega`. What is the cell constant if conductivity of `0.001M KCl` solution at `298K` is `0.146 xx 10^(-3)S cm^(-3) S cm^(-1)`.

Explanation

Cell constant , `G^(**) = ("Conductivity")/("Conductance")`
Conductance = `(1)/(1500) S`
`therefore` Cell constant = `(0.146 xx 10^(-3) S cm^(-1))/(1//1500)`
`= 0.219 cm^(-1)`