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10800 C of electricity passed through th...

`10800 C` of electricity passed through the electrolyte deposited `2.977g` of metal with atomic mass `106.4 g mol^(-1)`. The charge on the metal cation is

A

4

B

3

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
`2.977` g of metal require = 10800 C
`106.4` g of metal require = `(10800)/(2.977) xx 106.4`
`= 3.86 xx 10^(5) C `
Valency = `(3.86 xx 10^(5))/(96500) = 4`
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