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The half-life of a radioactive nuclide i...

The half-life of a radioactive nuclide is 20 hours. What fraction of original activity will remain after 40 hours?

A

`(1)/(6)`

B

`(1)/(8)`

C

`(1)/(4)`

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
We have, `(t)/(t_(1//2)) = ("40 hours")/("20 hours") = 2`
Thus, `A = (A_(0))/(2^(t//t_(1//2))) = (A_(0))/(2^(2)) = (A_(0))/(4) or, (A)/(A_(0)) = (1)/(4)`
So, one-fourth of the original activity will remain after 40 hours.
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