Home
Class 10
MATHS
Prove that the parallelogram circumscrib...

Prove that the parallelogram circumscribing a circle is a rhombus.

Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    VK GLOBAL PUBLICATION|Exercise HOTS (Higher Order Thinking Skills)|4 Videos
  • CIRCLES

    VK GLOBAL PUBLICATION|Exercise PROFICIENCY EXERCISE (Very Short Answer Questions 1 mark)|13 Videos
  • CIRCLES

    VK GLOBAL PUBLICATION|Exercise SHORT ANSWER QUESTIONS - II (3 marks)|13 Videos
  • ARITHMETIC PROGRESSIONS

    VK GLOBAL PUBLICATION|Exercise SELF ASSESSMENT TEST|10 Videos
  • COORDINATE GEOMETRY

    VK GLOBAL PUBLICATION|Exercise SELF-ASSESSMENT TEST|10 Videos

Similar Questions

Explore conceptually related problems

If all the side of a parallelogram touch a circle, show that the parallelogram is a rhombus.OR Prove that a parallelogram circumscribing a circle is a rhombus.

Assertion(A) If two tangents are drawn to a circle from an external point then they subtend equal angles at the centre. Reason (R ) A parallelogram circumscribing a circle is a rhombus

Prove that the rectangle circumscribing a circle is a square

Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.

Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.

Prove that opposite sides of a quadrilateral circumscribing a circle,subtend supplementary angles at the centre of a circle.

Rhombus a parallelogram having all sides equal is called a rhombus.

Rhombus a parallelogram having all sides equal is called a rhombus.

Prove that the centre of the circle circumscribing the cyclic rectangle ABCD is the point of intersection of its diagonals.