`5(1)/(7)-{3(3)/(10)-:(2(4)/(5)-(7)/(10))}`

[[1,0,-13,4,50,-6,-7]]=[[(1)/(10),(3)/(10),(1)/(5)(21)/(20),-(7)/(20),-(2)/(5)-(9)/(10),(3)/(10),(1)/(5)]]

Solve (i) 2-(3)/(5)(ii)4+(7)/(8)(iii)(3)/(5)+(2)/(7)(iv)(9)/(11)-(4)/(5)(v)(7)/(10)+(2)/(5)+(3)/(2)(vi)(2)(2)/(3)+(3)(1)/(2) (vii) (8)(1)/(2)-(3)(5)/(8)

Verify the following: (i) ((3)/(4)+(-2)/(5))+(-7)/(10)=(3)/(4)+((-2)/(5)+(-7)/(10)) (ii) ((-7)/(11)+(2)/(-5))+(-13)/(22)=(-7)/(11)+((2)/(-5)+(-13)/(22)) (iii) -1+((-2)/(3)+(-3)/(4))=(-1+(-2)/(3))+(-3)/(4)

The arrangement of rational numbers (-7)/(10),(5)/(-8),(2)/(-3) in ascending order is (2)/(-3),(5)/(-8),(-7)/(10) (b) (5)/(-8),(-7)/(10),(2)/(-3) (c) (-7)/(10),(5)/(-8),(2)/(-3)(d)(-7)/(10),(2)/(-3),(5)/(-8)

(3)/(10)+(7)/(10^(2))+(3)/(10^(3))+(7)/(10^(4))+(3)/(10^(5))+(7)/(10^(6))+

Simplify : ((1)/(12) + ((-3)/( 4)) + (7)/(8)) xx (3 (2)/(5) - (7)/(10) + ((-2)/( 15)) - 10 (1)/(30))

The value of 6((1)/(5)) - [4((1)/(2)) - {""((1)/(6)) - (""((3)/(5)) + ""((3)/(10)) - ""((7)/(15)))}] is

Find the sum of the infinite series (7)/(5)(1+(1)/(10^(2))+(1.3)/(1.2).(1)/(10^(4))+(1.3.5)/(1.2.3).(1)/(10^(6))+....)

Find the sum of the infinite series (7)/(5)(1+(1)/(10^(2))+(1.3)/(1.2).(1)/(10^(4))+(1.3.5)/(1.2.3).(1)/(10^(6))+....)