Solve `sin^(2) theta-cos theta=1/4, 0 le theta le 2pi`.

sin theta -2 = cos2theta when 0 le theta le 2pi

Solve sin^2 theta- cos theta =1/4 " for " theta and write the value of theta in the interval 0 le theta le 2 pi

Solve cos theta * cos 2 theta * cos 3 theta = (1)/( 4), 0 le theta le pi

Solve cos theta * cos 2 theta * cos 3 theta = (1)/( 4), 0 le theta le pi

Solve cos theta * cos 2 theta * cos 3 theta = (1)/( 4), 0 le theta le pi

Solve : cos theta cos 2 theta cos 3 theta =(1)/(4) (0 le theta le pi)

If 6sin^(2)theta - sin theta = 1 and 0 le theta le pi , what is the value of sin theta ?