Two charged particles are attached to an x axis: Particle 1 of charge `-4.00 xx 10^(-7) C` is at position x = -5.00 cm and particle 2 of charge `+4.00 xx 10^(-7)C` is at position x = 10.cm. Midway between the particles, what is their net electric field in unit-vector notation ?

Explanation

To find the net electric field at the midpoint between two charged particles, we can follow these steps:

### Step 1: Identify the positions and charges of the particles.
- Particle 1 (P1) has a charge of \( q_1 = -4.00 \times 10^{-7} \, C \) located at \( x_1 = -5.00 \, cm \) (or -0.05 m).
- Particle 2 (P2) has a charge of \( q_2 = +4.00 \times 10^{-7} \, C \) located at \( x_2 = 10.00 \, cm \) (or 0.10 m).

### Step 2: Calculate the midpoint between the two particles.
- The distance between the two particles is \( d = x_2 - x_1 = 0.10 - (-0.05) = 0.15 \, m \).
...