`sin((1+x^(2))/(1-x^(2)))`

(d)/(dx) {sin ^(2) ((1- x ^(2))/(1 + x ^(2)))}=

The value of cos[2tan^(-1)(1+x)/(1-x)+sin^(-1)(1-x^(2))/(1+x^(2))] is

y = sin ^(-1)((1 - x^(2))/(1+ x^(2))) 0 lt x lt 1

If x_(1) = 2 tan^(-1) ((1 + x)/(1 -x)), x_(2) = sin^(-1) ((1 - x^(2))/(1 + x^(2))), " where " x in (0, 1) , then x_(1) + x_(2) is equal to

simplify 2tan^(-1)((1+x)/(1-x))+sin^(-1)((1-x^(2))/(1+x^(2)))

Differentiate the following : y=sin^(-1)((1-x^(2))/(1+x^(2)))

The derivative of sin^(-1) ((2x)/(1+x^(2))) w.r.t sin^(-1) ((1-x^(2))/(1+x^(2))) is

Prove that 2tan^(-1)((1+x)/(1-x))+sin^(-1)((1-x^(2))/(1+x^(2)))=pi