" b) "H_(2)(g)+Br_(2)(g)rarr2HBr(g),Delta H=-72.98KJ/" mole "

H_(2)(g)+Br_(2)(g) rarr 2HBr(g), DeltaH^(Theta) =-72.40 kJ DeltaG^(Theta) = - 106.49 kJ, T - 298 K The value DeltaS is ………. .

H_(2)(g)+Br_(2)(g) rarr 2HBr(g), DeltaH^(Theta) =-72.40 kJ DeltaG^(Theta) = - 106.49 kJ, T = 298 K The value DeltaS is ………. .

Calculate the entropy of Br_(2)(g) in the reaction H_(2)(g)+Br_(2)(g)rarr2HBr(g), Delta S^(@)=20.1 JK^(-1) given, entropy of H_(2) and HBr is 130.6 and 198.5 J mol^(-1)K^(-1) :-

Calculate the entropy of Br_(2)(g) in the reaction H_(2)(g)+Br_(2)(g)rarr2HBr(g), Delta S^(@)=20.1 JK^(-1) given, entropy of H_(2) and HBr is 130.6 and 198.5 J mol^(-1)K^(-1) :-

H_(2)(g)+I_(2) (s) rarr 2HI (g), DeltaH=51.9 KJ/mole H_(2)(g)+I_(2)(g) rarr 2 HI (g), DeltaH=-9.2 kJ/mole. the heat of reaction of I_(2)(s) rarr I_(2) (g)

The average O-H bond energy in H_(2)O with the help of following data. (1) H_(2)O(l)rarrH_(2)O(g), Delta H= +40.6 kJ mol^(-1) (2) 2H(g)rarrH_(2)(g), DeltaH= -435.kJ mol^(-1) (3) O_(2)(g)rarr2O(g), Delta H= +489.6 kJ mol^(-1) (4) 2H_(2)(g)+O_(2)(g)rarr2H_(2)O(l), Delta H= -571.6 kJ mol^(-1)

Calculate Delta H^(theta) for the reaction : H_(2)O (l) rarr H_(2)(g) + (1)/(2) O_(2) (g) Given 2H_(2)(g) + O_(2)(g) rarr 2H_(2)O(l) Delta H = -571.6 kJ

Given, H_(2)(g)+Br_(2)(g)rarr2HBr(g),DeltaH_(1)^(0) and standard enthalpy of condensaion of bromine is DeltaH_(2)^(0) , standard enthalpy of formation of HBr at 25^(@)C is